(2x^2+4x)-(x^2+5x-10)=0

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Solution for (2x^2+4x)-(x^2+5x-10)=0 equation: 



(2x^2+4x)-(x^2+5x-10)=0

We get rid of parentheses

2x^2-x^2+4x-5x+10=0

We add all the numbers together, and all the variables

x^2-1x+10=0

a = 1; b = -1; c = +10;
Δ = b2-4ac
Δ = -12-4·1·10
Δ = -39
Delta is less than zero, so there is no solution for the equation

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